Question

(-4,5) is a vertex of a square and one of its diagonals is 7x-y+8=0. find the equation of the other diagonal.

Answer 1

Description for Correct answer

Equation of perpendicular line to
 7x−y+8=0
7x−y+8=0 
is x+7y=hx+7y=h 
which is passes through 
(−4, 5)(−4, 5) 

h = 31 

Answer 2

Thank you for asking this question.

The options for this question are missing. Following are the missing options:

A) x+3y=21

B) 2x−3y=7

C) x+7y=31

D) 2x+3y=21

The correct answer is   B) 2x−3y=7

Reason:

Equation of perpendicular line to 7x−y+8=0 is x+7y=h which is passes through (−4, 5)  

h = 31  

So, equation of another diagonal is x+7y = 31