Question

4.5 moles each of hydrogen and iodine are heated in a sealed 10 litre vessel. At equilibrium, 3 moles of hydrogen iodide was found. The equilibrium constant for h2 (g) + i2 (g) 2 hi (g) is

Answer 1

Hey dear,

● Answer -
Kc = 1



● Explanation -
Formation of hydrogen iodide occurs as follows -
Reaction : H2 + I2 --> 2HI
Initially : 4.5 4.5 0
Equilibrium : 4.5-x 4.5-x 2x

Given that -
[HI] = 2x = 3 mol, ∴ x = 1.5 mol
[H2] = 4.5-x = 4.5-1.5 = 3 mol
[I2] = 4.5-x = 4.5-1.5 = 3 mol

Equilibrium constant for the reaction -
Kc = [HI]^2 / [H2][I2]
Kc = 3^2 / (3×3)
Kc = 1

Therefore, equilibrium constant for the reaction is 1.

Answer 2

Answer:

the correct answer is 1

Explanation:

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