Math, asked by soniastudent1999, 8 months ago

(4+5)squ2का मान ज्ञात करो पूरा

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Answered by Anonymous

Answer:

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$(4 + 5) {}^{2}$

$= > (x + y) {}^{2} = {x}^{2} + 2xy + {y}^{2}$

$= > (4) {}^{2} + 2 (4 \times 5) +( {5})^{2}$

$= > 16 + 40 + 25$

$= > 81$

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(4+5)squ2का मान ज्ञात करो पूरा​

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(4+5)squ2का मान ज्ञात करो पूरा