Question

(4/5a-2)3 Expand factorisation of polynomials.
plzz help me

Answer 1

${( \frac{4}{5}a - 2 )}^{3} \\ \\ \\ {( \frac{4}{5}a)}^{3} - {2}^{3} - 3( \frac{4}{5}a )(2)[ \frac{4}{5}a - 2] \\ \\ \frac{ {64a}^{3} }{125} - 8 - \frac{24a}{5}(\frac{4}{5}a - 2) \\ \\ \frac{ {64a}^{3} }{125} - \frac{ {96a}^{2} }{25} + \frac{48a}{5} - 8$