Question

4√5x^2-24x-9√5=0, find the zeros polynomial.​

Answer 1

thankyou hope this may help you

Answer 2

Answer:

Zeros of polynomial is $-\frac{3}{2\sqrt{5} }$ and $\frac{3\sqrt{5} }{2}$.

Step-by-step explanation:

Given: Polynomial equation, $P(x)=4\sqrt{5} x^{2} -24x-9\sqrt{5} =0$.

Find: The zeros polynomial

A polynomial function is a function that involves only non-negative integer powers or only positive integer exponents of a variable in an equation like the quadratic equation, cubic equation, etc.

For a polynomial P(x), real number k is said to be zero of polynomial P(x), if $P(x) = 0$.

All the x-values that bring a polynomial, p(x), to zero are referred to as its zeros. They are intriguing to us for a variety of reasons, one of which is that they provide information on the graph's x-intercepts for the polynomial. We will also observe that they have a direct connection to the polynomial's factors.

$4\sqrt{5} x^{2} -24x-9\sqrt{5} =0$

$4\sqrt{5} x^{2} -30x+6x-9\sqrt{5} =0\\2\sqrt{5} x(2x-3\sqrt{5} )+3(2x-3\sqrt{5} )=0\\(2\sqrt{5} x+3)(2x-3\sqrt{5} )=0$

Zeros of factors of polynomial P(x)

$(2\sqrt{5} x+3)=0\\2\sqrt{5} x=-3\\x=-\frac{3}{2\sqrt{5}}$

$2x-3\sqrt{5} =0\\2x=3\sqrt{5} \\x=\frac{3\sqrt{5}}{2}$

Hence, zeros of polynomial is $-\frac{3}{2\sqrt{5} }$ and $\frac{3\sqrt{5} }{2}$

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