Math, asked by hijabwaseem09, 2 months ago

4(5x – 3y) (x – 4y) – (3x – 4y) (2x +3y)

Answers

Answered by Shivali2708
2

4(5x – 3y) (x – 4y) – (3x – 4y) (2x +3y)

= 4 ( 5x² - 3xy - 20xy +12y²) - (6x² - 8xy + 9xy - 12y²)

= 4 ( 5x² -23xy +12y²) - (6x² +1xy - 12y²)

= 20x² -92xy + 48y² - 6x² - 1xy +12y²

= 20x² - 6x² -92xy - 1xy + 48y² + 12y²

= 14x² -93xy + 60y²

hope it helps..

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