Question

4×6.022×10 raise23 chlorine molecules at STP are taken. What is the volume of STP

Answer 1

To find:

Volume of 4 × 6.022 × 10²³ chlorine molecules at STP.

Calculation:

First we need to calculate the total moles of chlorine molecules present in the system;

$\rm{\therefore \: moles = \dfrac{4 \times 6.022 \times {10}^{23} }{avagadro \: number} }$

$\rm{ = > \: moles = \dfrac{4 \times 6.022 \times {10}^{23} }{6.022 \times {10}^{23} } }$

$\rm{ = > \: moles = 4 \: mol }$

Now , we know that 1 mole of any gas at STP will have a volume of 22.4 L ;

So, net volume of Chlorine gas :

$\rm{volume = mol \times 22.4}$

$\rm{ = > volume = 4\times 22.4}$

$\rm{ = > volume = 89.6 \: litres}$

So, final answer is:

$\boxed{\bf{volume = 89.6 \: litres}}$