4,6-dimethyl - 5 - hydroxy - 3 - heptenal structure
Answers
We know that according to Ohm’s law
V = IR
where
V= potential difference
I= Current
R = Resistance
We can also modify the equation as
I=V/R ——- (i)
Now given that the potential difference across the two ends of the component decreases to half
∴ So let the new potential difference be Vʹ=V/2
Resistance remains constant across the electrical component
So the new current is drawn through the electrical component is Iʹ = Vʹ/R
= (V/2)/R {Substituting Vʹ=V/2 in the above equation}
= (1/2) (V/R)
= (1/2) I = I/2
Therefore, the amount of current flowing through the electrical component is reduced by half.
Answer:
Width of rectangle is 25 cm.
Step-by-step explanation:
Given :-
A wire bend in form of square of side 30 cm.
Then wire is again bend in form of rectangle of length 35 cm.
To find :-
Width of the rectangle.
Solution :-
Here, Concept is : If we are bending wire in form of square than again bending it in rectangle. Than, perimeter of square will equal to perimeter of rectangle because we are not increasing length of wire by one measure we are bending it in square and rectangular shape.
So,
Perimeter of square = 4 × side
⟶ Perimeter = 4 × 30
⟶ Perimeter = 120
Thus,
Perimeter of square is 120 cm.
According to concept, Perimeter of square and perimeter of rectangle are equal.
So, Perimeter of rectangle is 120 cm.
Let, Breadth or width or rectangle be x cm.
We know,
Perimeter of rectangle = 2(Length + Breadth)
⟶ 120 = 2×(35 + x)
⟶ 120 = 70 + 2x
\⟶ 120 - 70 = 2x
⟶ 50 = 2x
⟶ 50/2 = x
⟶ x = 25
We take, Width of rectangle be x.
Therefore,
Width of rectangle is 25 cm.