Question

4.6x10^22 atoms of an elements weigh 13.8 g. The atomic mass of the element is
(approximately)

Please answer the question.
Please

Answer 1

Hyy Dude

Given that 4.6 * 10^22 atoms of an element weight = 13.8gm.

Then the weight of 1 element = 13.8/4.6 * 10^22

                                                  = 3 /10^22

We know that the number of moles = number of atoms/6.02 * 10^23

                                                            = 3 * 6.02 * 10^23/10^22

                                                            = 180.6g

Hope this helps

Plz marked in brainlest answer

Answer 2

★$\color{darkblue}\underline{\underline{\sf Given-}}$

• Number of atoms (N) = 4.6×10²²
• Weight of element (m) = 13.8g

★$\color{darkblue}\underline{\underline{\sf To \: Find-}}$

• Atomic Mass

━━━━━━━━━━━━━━━━━━━━━━━━━━━

★$\color{darkblue}\underline{\underline{\sf Formula \: Used-}}$

$\color{violet}\bullet\underline{\boxed{\sf No. \; of \: atoms(N)=Mole×N_A}}$

${\sf N_A=Avogadro \: Number = 6.023×10^{23}}$

$\color{violet}\bullet\underline{\boxed{\sf Mole\:(n)=\dfrac{Mass}{Molecular \: Mass}}}$

━━━━━━━━━━━━━━━━━━━━━━━━━━━

★$\color{darkblue}\underline{\underline{\sf Solution-}}$

$\implies{\sf No. \: of \: atoms = n×N_A }$

$\implies{\sf n=\dfrac{4.6×10^{22}}{6.023×10^{23}}}$

$\color{orange}\implies{\sf n=0.07}$

$\implies{\sf Mole (n)=\dfrac{Mass}{Molecular \: Mass} }$

$\implies{\sf 0.07=\dfrac{13.8}{M_w} }$

$\implies{\sf M_w=\dfrac{13.8}{0.07} }$

$\color{red}\implies{\sf M_w=197.1\:g}$

★$\color{darkblue}\underline{\underline{\sf Answer-}}$

Atomic Mass of the element is $\color{red}{\sf 197.1\:g}$