Question

√4^-7×√2^-5

solve this problem in step​

Answer 1

Answer:

$2^{\frac{-19}{2}}$

Step-by-step explanation:

$(\sqrt{4})^{-7} \times (\sqrt{2})^{-5}\\\\\\= 2^{-7} \times (2)^{\frac{1}{2} \times (-5)}\\\\\\= 2^{-7} \times 2^{- \frac{5}{2}}\\\\\\= 2^{-7 - \frac{5}{2}} = 2^{\dfrac{-14-5}{2}} = 2^{\frac{-19}{2}}$