Question

4/7×7/6×8/9+1/4 solve by normal
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Answer 1

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$

4/7×7/6×8/9+1/4 solve by normal

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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$\bold{= > \frac{4}{7} \times \frac{7}{6} \times \frac{8}{9} + \frac{1}{4} }$

$\bold{= > \frac{28}{42} \times \frac{8}{9} + \frac{1}{4}}$

L.C.M OF 9 & 4 IS 36.

$\bold{ = > \frac{28}{42} \times \frac{32 + 9}{36}}$

Here ,28/42 is divided by 7

$\bold{= > \frac{4}{6} \times \frac{41}{36}}$

=>here ,36 gets cancelled by 4

$\bold{= > \frac{1}{6} \times \frac{41}{9} = \frac{41}{54}}$

Your final answer is 41/54

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