Question

4/7 of the girls and 2/5 of the boys of a primary school participated in the annual sports .if the number of partipating students is 420 out of which 124 are boys ,what is the total number of students in the primary school
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Answer 1

Answer:

There are 828 students in the primary school .

Step-by-step explanation:

Let the number of girls be x and the number of boys be y.

The number of students participating is, N = 420.

Number of boys participating n (Y) = 124

Number of girls participating n (X) = N - n (Y) = 420 - 124 = 296.

It is provided that:

$\frac{4}{7} x=296$

Solve for x as follows:

$\frac{4}{7} x=296\\x=\frac{296\times7}{4} \\=518$

It is provided that:

$\frac{2}{5} y=124\\y=\frac{124\times5}{2}\\=310$

Solve for x as follows:

$\frac{4}{7} x=296\\x=\frac{296\times7}{4} \\=518$

The total number of students in the school is:

$Total\ no.\ of\ students=x+y=518+310=828$

Thus, there are 828 students in the primary school .