4/7 part of a pole is in the earth. When 1/4 of this part is pulled out, 5/2 metres of the pole is still in the earth . What is the full length of the pole?
Answers
✿◕ ‿ ◕✿H⃤ E⃤ Y⃤ M⃤ A⃤ T⃤ E⃤
Here is your answer :-
Let us assume length of pole is L.
Let us assume length of pole is L.Length of the pole in Mud is = L x 4/7 = 4L/7
Let us assume length of pole is L.Length of the pole in Mud is = L x 4/7 = 4L/7Length of the Pole which is pulled out = L x 1/3 = L/3
Let us assume length of pole is L.Length of the pole in Mud is = L x 4/7 = 4L/7Length of the Pole which is pulled out = L x 1/3 = L/3Length of the pole is still in mud = Length of the pole in Mud - Length of the Pole which is pulled out
Let us assume length of pole is L.Length of the pole in Mud is = L x 4/7 = 4L/7Length of the Pole which is pulled out = L x 1/3 = L/3Length of the pole is still in mud = Length of the pole in Mud - Length of the Pole which is pulled outLength of the pole is still in mud = 4L/7 - L/3
Let us assume length of pole is L.Length of the pole in Mud is = L x 4/7 = 4L/7Length of the Pole which is pulled out = L x 1/3 = L/3Length of the pole is still in mud = Length of the pole in Mud - Length of the Pole which is pulled outLength of the pole is still in mud = 4L/7 - L/3According to question,
Let us assume length of pole is L.Length of the pole in Mud is = L x 4/7 = 4L/7Length of the Pole which is pulled out = L x 1/3 = L/3Length of the pole is still in mud = Length of the pole in Mud - Length of the Pole which is pulled outLength of the pole is still in mud = 4L/7 - L/3According to question,Length of the pole is still in mud = 250
Let us assume length of pole is L.Length of the pole in Mud is = L x 4/7 = 4L/7Length of the Pole which is pulled out = L x 1/3 = L/3Length of the pole is still in mud = Length of the pole in Mud - Length of the Pole which is pulled outLength of the pole is still in mud = 4L/7 - L/3According to question,Length of the pole is still in mud = 2504L/7 - L/3 = 250
Let us assume length of pole is L.Length of the pole in Mud is = L x 4/7 = 4L/7Length of the Pole which is pulled out = L x 1/3 = L/3Length of the pole is still in mud = Length of the pole in Mud - Length of the Pole which is pulled outLength of the pole is still in mud = 4L/7 - L/3According to question,Length of the pole is still in mud = 2504L/7 - L/3 = 250 (4L x 3 - L x 7)/7 x 3 = 250
Let us assume length of pole is L.Length of the pole in Mud is = L x 4/7 = 4L/7Length of the Pole which is pulled out = L x 1/3 = L/3Length of the pole is still in mud = Length of the pole in Mud - Length of the Pole which is pulled outLength of the pole is still in mud = 4L/7 - L/3According to question,Length of the pole is still in mud = 2504L/7 - L/3 = 250 (4L x 3 - L x 7)/7 x 3 = 250 12L - 7L = 250 x 21
Let us assume length of pole is L.Length of the pole in Mud is = L x 4/7 = 4L/7Length of the Pole which is pulled out = L x 1/3 = L/3Length of the pole is still in mud = Length of the pole in Mud - Length of the Pole which is pulled outLength of the pole is still in mud = 4L/7 - L/3According to question,Length of the pole is still in mud = 2504L/7 - L/3 = 250 (4L x 3 - L x 7)/7 x 3 = 250 12L - 7L = 250 x 215L = 250 x 21
Let us assume length of pole is L.Length of the pole in Mud is = L x 4/7 = 4L/7Length of the Pole which is pulled out = L x 1/3 = L/3Length of the pole is still in mud = Length of the pole in Mud - Length of the Pole which is pulled outLength of the pole is still in mud = 4L/7 - L/3According to question,Length of the pole is still in mud = 2504L/7 - L/3 = 250 (4L x 3 - L x 7)/7 x 3 = 250 12L - 7L = 250 x 215L = 250 x 21L = 250 x 21/5
Let us assume length of pole is L.Length of the pole in Mud is = L x 4/7 = 4L/7Length of the Pole which is pulled out = L x 1/3 = L/3Length of the pole is still in mud = Length of the pole in Mud - Length of the Pole which is pulled outLength of the pole is still in mud = 4L/7 - L/3According to question,Length of the pole is still in mud = 2504L/7 - L/3 = 250 (4L x 3 - L x 7)/7 x 3 = 250 12L - 7L = 250 x 215L = 250 x 21L = 250 x 21/5L = 50 x 21
Let us assume length of pole is L.Length of the pole in Mud is = L x 4/7 = 4L/7Length of the Pole which is pulled out = L x 1/3 = L/3Length of the pole is still in mud = Length of the pole in Mud - Length of the Pole which is pulled outLength of the pole is still in mud = 4L/7 - L/3According to question,Length of the pole is still in mud = 2504L/7 - L/3 = 250 (4L x 3 - L x 7)/7 x 3 = 250 12L - 7L = 250 x 215L = 250 x 21L = 250 x 21/5L = 50 x 21L = 1050
(✿◠‿◠)ɪ ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ!!ᴘʟᴇᴀsᴇ ᴍᴀʀᴋ ɪᴛ ᴀs ʙʀᴀɪɴʟɪᴇsᴛ!!!
Answer:
iihuvtf fr
vt8v7tc
Step-by-step explanation:
govt v6g6v6tv6v6tv7h