Question

(4/7)to the power of-5 × (7/4)to the power of- 7

Answer 1

(4/7)^-5
= (7/4)^5
(7/4)^-7
= (4/7)^7
(7/4)^5 ×(4/7)^7
7^5/4^5 × 4^7/7^7
4^7×4^-5 / 7^7×7^-5
4^2/7^2
=16/49 is answer

Answer 2

$( \frac{4}{7} ) {}^{ - 5} \times ( \frac{7}{4} ) {}^{ - 7} \\ ( \frac{4}{7} ) {}^{ - 5} \times ( \frac{4}{7} ) {}^{7} \\ ( \frac{4}{7} ) {}^{7 - 5} \\ ( \frac{4}{7} ) {}^{2} \\ \frac{16}{49}$
hope this helps you.
don't forget to do it brainleist.