4) 7h resultant of two forces at night angles a 0.05kg-ot
of one of the forces makes an angle of 30
with the resultant
Calacoste the forces -
[0.0433 and 0.025 kg-wit]
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sorry I didn't understand your question sorry
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if one angle is 90° and one angle 30° then the third angle is 60°
Let one force be a and other force be b
sin60°=a/0.05
=> a=√3/2×0.05=0.0433kg wt
Similarly cos 60° =b/0.05
=> b=1/2×0.05=0.025kgwt.
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