4+8+12......+160
What is the sum?????
Answers
Answered by
2
Answer:
Step-by-step explanation:
A is 1st term
L is last term
n is number of terms
d is common difference
nth term= A + (n- 1 )d
160 = 4 + ( n-1) 4
156 = (n - 1) 4
39 = n-1
n=40
sum = n/2 ( A+ L)
= 40 / 2 ( 160 + 4)
= 20 ( 164)
= 3280
hope it helps
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Answered by
0
Answer:
very good nalla chodhyam adutha chodhyam
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