Question

(4+8+12)omega minimum value kya hoga

Answer 1

Heya folk !!

Here's the answer you are looking for

The value of sum of resistance is minimum when they are coonected in a parallel connection.

$\frac{1}{R} = \frac{1}{ R_{1} } + \frac{1}{ R_{2} }$ +\frac{1}{ R_{3} } [/tex] +....+ \frac{1}{ R_{n} } [/tex] 

So, here the minimum value is

$\frac{1}{R} = \frac{1}{ 4 } + \frac{1}{ 8 }$ + \frac{1}{ 12 } [/tex] 
                         = \frac{6+3+2}{ 24 } [/tex] 
                         = \frac{11}{24} [/tex] 


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