Physics, asked by 007Tanzin, 10 months ago

4. 8 A of current is flowing in a long straight wire. A positive charge, q = 7 C is moving parallel to the wire at a distance of 0.05 m with a velocity of 250 ms-1. Calculate the magnitude of the magnetic field due to the flow of current in the wire.
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please any one help me by solving this ​

Answers

Answered by ylvell
0

Answer:

sorry dear.. question is very difficult.i don't k

Answered by PoojaBurra
0

Given :

Magnitude of current flowing in the wire = 8A

Magnitude of the positive charged particle = 7C

Distance of the wire = 0.05 m

Velocity of the charged particle = 250 m/s

To Find :

The magnetic field due to the flow of current in the wire

Solution :

  • Magnetic field due to the current carrying wire is given by

                 B=\frac{\mu_{0}I}{2\pi R}

  • By substituting the values in the above equation

                 B=\frac{4 \pi  \times 10^{-7}\times8}{2\pi \times0.05}

                 B=3.2\times10^{-5}\:T

The magnetic field due to the flow of current in the wire is 3.2×10⁻⁵ T.

         

   

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