Question

4.8 g of oxygen is adsorbed on 1.2 g of metal
powder. The volume of oxygen adsorbed per gram
of the adsorbent at NTP is
(1) 2.8 L
(2) 3.6 L
(3) 4.6 L
(4) 3.2 L​

Answer 1

Answer:

my and your question is different

but you can solve at my concept

Explanation:

Mass of oxygen adsorbed per gram of metal powder =

1.2

3.6

g=3g=m

By ideal gas equation, PV=nRT

∴V=

MP

mRT

=

32×1 atm

3×273×0.0821

=2.1 Lg

−1

Option C is the correct answer.