Question

4.8 g of oxygen is adsorbed on 1.2 g of metal
powder. The volume of oxygen adsorbed per gram
of the adsorbent at NTP is ​

Answer 1

Answer:

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Answer 2

Explanation:

Given 4.8 g of oxygen is adsorbed on 1.2 g of metal powder. The volume of oxygen adsorbed per gram  of the adsorbent at NTP is

• So we have
•                Metal + Oxygen will give metal oxide.
•     Now 1.2 g of metal powder is absorbed by 4.8 g of oxygen.
• So for 1 gm it will be 4.8 /1.2
•                                   = 4 gm
• So for oxygen gas we have
•                                PV = W/M R T
•                                1 x V = 4 / 32 x 0.0821 x 273
•                                               V = 2.8 L/gm

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https://brainly.in/question/21999159