Question

4.8 g of oxygen is adsorbed on 12 g of metal powder. The volume of oxygen adsorbed per gram of the adsorbent at NTP is ​

Answer 1

Given:

The mass of oxygen adsorbed = 4.8 gm

The mass of metal powder = 12 gm

To Find:

The volume of oxygen adsorbed per gram of the adsorbent at NTP.

Calculation:

- The mass of oxygen adsorbed per gram of metal powder = 4.8/12 = 0.4 gm/gm

- The volume of 32 gm (1 mole) of oxygen = 22.4 L

- The volume of 0.4 gm of oxygen = (22.4/32) × 0.4

⇒ V = 0.28 L

 

- So, the volume of oxygen adsorbed per gram of adsorbent is 0.28 L.