Question

4) 804 cm?
The length of the diagonal of a quadrilateral is 40 cm
and the perpendicular drawn to it from the opposite
vertices are 12 cm and 7.5 cm. Find the area of
the quadrilateral draw to it from the opposite vertices are 12 cm and 7. 5 cm​

Answer 1

Answer:

Given:-

In a Quadiratral

• Length of a diagonal =40cm
• Length of perpendicular drawn to it from opposite vertices = 12cm and 7.5cm

To find:-

Area of the Quadiratral

Solution:-

As we know that in a Quadiratral

${\boxed{\sf Area=\dfrac {1}{2}\times Diagonal \times sum\:of\:the\:length\:of\:perpendiculars\:drawn\:from\:opposite\:vertices}}$

• Substitute the values

${:}\longrightarrow\sf Area=\dfrac {1}{2}\times 40 \times (12+7.5)$

• Simplify

${:}\longrightarrow\sf Area=\dfrac {1}{\cancel {2}}\times \cancel{40} \times 19.5$

${:}\longrightarrow\sf Area=20\times 19.5$

${:}\longrightarrow\bf Area=390cm^2$

$\therefore\underline{\underline{\sf Ares\;of\:the\;quadiratral\:is 390cm^2.}}$

Explore more:-

Quadiratral:-

• The polygon in a plane which has four sides and four vertices is called Quadiratral .
• The sum of interior angles of a Quadiratral is 360°.
• Some Quadiratral Examples are=Square,Rectangle,Rhombus,Parallelogram,Trapezium.