Question

4.83 A current is passed through 1 L, 1 M aqueous solution of KCl for 200 seconds. Assuming that there is no change in volume during electrolysis, the pH of the resulting solution is

Answer 1

Explanation:

Using Faraday's law:

∴ Eq. of Zn

2+

lost =

96500

i.t

=

100×96500

1.70×90×230

=3.647 × 10

−3

∴ Meq. of Zn

2+

lost =3.647

Initial Meq. of Zn

2+

= 300 × 0.160 × 2 =96 (Valence factor = 2)

Meq. of Zn

2+

left in solution =96−3.647=92.353

∴ [ZnSO

4

] =92.353/(2×300)=0.154 M