Question

(4/9)^4*(4/9)^-7=(4/9)^2x-1

Answer 1

Hey friend,
Here is the answer you were looking for:
${( \frac{4}{9} )}^{4} \times { (\frac{4}{9}) }^{ - 7} = {( \frac{4}{9}) }^{2x - 1} \\ \\ as \: the \: bases \: are \: same \: then \: the \: powers \: are \: same \\ \\ 4 + ( - 7) = 2x - 1 \\ \\ 4 - 7 = 2x - 1 \\ \\ - 3 + 1 = 2x \\ \\ - 2 = 2x \\ \\ \frac{ - 2}{2} = x \\ \\ - 1 = x \\ \\ x = - 1$

Hope this helps!!!

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Answer 2

IF BASES ARE SAME THEN THE POWERS ARE ALSO SAME

SO ,

4+(-7) =   2x-1

4-7     =   2x-1

(-3)     =   2x-1

2x = (-1)-(-3)

    = (-1)+3

    =(-2)

∴ x = (-2/2)

     = (-1)

SO VALUE OF X IS (-1)

HOPE IT HELPS YOU

THANKYOU