(4/9 abc3)×(-27/5 a3b2)×(-8b3c)
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Answer: Get answer: If 27 abc> (a+b+c)^3 and 3a +4b +5c=12 then 1,a^2+1,b^3+1,c^5=10, where a, b, c are positive real numbers. Statement-2: For
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Answer:
: If 27 abc> (a+b+c)^3 and 3a +4b +5c=12 then 1,a^2+1,b^3+1,c^5=10, where a, b, c are positive real numbers. Statement-2: For
Step-by-step explanation:
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