Math, asked by aritribhowmick08, 2 months ago

(4/9 abc3)×(-27/5 a3b2)×(-8b3c)

Answers

Answered by minergunder
1

Answer: Get answer: If 27 abc> (a+b+c)^3 and 3a +4b +5c=12 then 1,a^2+1,b^3+1,c^5=10, where a, b, c are positive real numbers. Statement-2: For

Step-by-step explanation:

Answered by 007sosforschoolonly
0

Answer:

: If 27 abc> (a+b+c)^3 and 3a +4b +5c=12 then 1,a^2+1,b^3+1,c^5=10, where a, b, c are positive real numbers. Statement-2: For

Step-by-step explanation:

Similar questions