4.9 g of H2SO4 is present in 500 cm3 of the
solution has molarity.
b) 0.1
d) 0.02
a) 0.2
c) 0.01
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Answers
Answered by
1
Answer:
0.2
Explanation:
hope help you this one is correct
Answered by
6
Answer:
answer will be 0.1M plz thnx my answer
given mass = 4.9g
molecular mass = 2+32+64 = 98
n(number of moles) = 4.9/98 = 1/20 mol
volume present = 500 cm^3 = 500/1000 = 0.5 litre or m^3
molarity = 1/20 dived by 0.5 = 0.1 M
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