Chemistry, asked by prathiravi123456, 3 months ago

4.9 gr H2SO4 is present in 100 ml of an aqueous solution. 10ml of the solution is

diluted to 1000ml with distilled water . Find the pH

of the dilution

A) 4 B) 2 C) 3 D) 7​

Answers

Answered by helenfaustina12
1

Answer:

Strength (g/L) of H

2

SO

4

=

100

4.9

×1000=49

Molarity=

Mol.mass

Strength

=

48

49

=0.5 M

Normality=n×Molarity

n=

Eq.mass

Mol.mass

=

49

98

=2

Normality=2×0.5=1.0

Hence, the H

2

SO

4

solution is 1 N.

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