Question

4
96. The length of perpendicular from the origin to a line is 5
units and the line makes an angle 120° with the positive
direction of x-axis. The equation of the line is
(a) x +✓3y = 5
(b) √3x +y =10
(C) √3x - y = 10
(d) None of these​

Answer 1

Answer:

Hyy there here's your answer

Given that OC=5

Angle made by line AB with positive x axis is 120

o

So, ∠CAO=180−120=60

o

In triangle OCA sum of angles =180

∠OCA+∠CAO+∠AOC=180

⟹90+60+∠AOC=180

⟹∠AOC=30

o

Slope of the line OC=tan30

o

=

3

1

Length of OC=5

Hence the point C which is in first quadrant will be

(0+5cos30

o

,0+5sin30

o

)

⟹C=(

2

5

3

,

2

5

)

The line having slope −

3

and passing through C=(

2

5

3

,

2

5

) shall become

y−

2

5

=−

3

(x−

2

5

3

)

⟹

3

x+y=10

Step-by-step explanation:

Hope that it helps you Nd kindly mark as the brainliest answer. :))