Math, asked by 7934, 7 months ago

(4/9abc3)×(-27/5a3b2)×(-8b3c)

Answers

Answered by mysticd
4

 Given \: \Big( \frac{4}{9} abc^{3}\Big) \times \Big( \frac{-27}{5} a^{3}b^{2}\Big) \times ( -8 b^{3}c)

 = \frac{4}{9} \times \Big( \frac{-27}{5}\Big) \times (-8) \times a\times a^{3} \times b \times b^{2}\times b \times c^{3} \times c

 = \frac{96}{5} a^{1+3} \times b^{1+2+3} \times c^{3+1}

 = \frac{96}{5} a^{4} \times b^{6} \times c^{4}

Therefore.,

 \red{\Big( \frac{4}{9} abc^{3}\Big) \times \Big( \frac{-27}{5} a^{3}b^{2}\Big) \times ( -8 b^{3}c)}

 \green { = \frac{96}{5} a^{4} \times b^{6} \times c^{4}}

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Answered by AgentMaths
1

Answer:

Hope it helps a lot....... ... .... . .....

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