Question

(4/9abc3)×(-27/5a3b2)×(-8b3c)
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Answer 1

$Given \: \Big( \frac{4}{9} abc^{3}\Big) \times \Big( \frac{-27}{5} a^{3}b^{2}\Big) \times ( -8 b^{3}c)$

$= \frac{4}{9} \times \Big( \frac{-27}{5}\Big) \times (-8) \times a\times a^{3} \times b \times b^{2}\times b \times c^{3} \times c$

$= \frac{96}{5} a^{1+3} \times b^{1+2+3} \times c^{3+1}$

$= \frac{96}{5} a^{4} \times b^{6} \times c^{4}$

Therefore.,

$\red{\Big( \frac{4}{9} abc^{3}\Big) \times \Big( \frac{-27}{5} a^{3}b^{2}\Big) \times ( -8 b^{3}c)}$

$\green { = \frac{96}{5} a^{4} \times b^{6} \times c^{4}}$

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Answer 2

Answer:

Hope it helps a lot....... ... .... . .....