Question

4.9g of H2SO4 in 500cm^3 of solution. Find malarity?

Answer 1

Correct question:-

4.9g of H₂SO₄ in 500cm³ of solution. Find molarity.

Answer:-

0.1M

Explanation:-

• Molar mass of Hydrogen (H) = 1g/mol

• Molar mass of Sulphur (S) = 32g/mol

• Molar mass of Oxygen (O) = 16g/mol

Hence, molar mass of H₂SO₄ :-

= 1×2+32+16×4

= 2+32+64

= 98g/mol

Number of moles in 4.9g of H₂SO₄ :-

= Given Mass/Molar mass

= 4.9/98

= 0.05 mole

Now, we know that:-

=> 1cm³ = 1mL

Thus, volume of the solution is 500mL.

Now, let's convert the volume of the solution from mL to L.

=> 1mL = 0.001L

=> 500mL = 500(0.001)

=> 0.5L

Molarity of a solution :-

= Moles of solute/Liters of solution

= 0.05/0.5

= 0.1M

Thus, molarity is 0.1M .