Chemistry, asked by induyadavmahak, 9 months ago

4.9g of NaOH is allowed to react with 6.022*10^22 molecules of H2SO4 according to the following reaction give the answers : 2NaOH + H2SO4= Na2SO4 + 2H2O A. find the limiting reagent? B. how much mass of limiting reagent is lesser than required ? C. what mass of excessory reagent will remain unreacted? D. what is the mass of Na2SO4 formed?

Answers

Answered by rekhayadav01817
0

Answer:

sorry, I don't know answer

Similar questions