Question

4(a − 1)2 – 4(a – 1) – 3​

Answer 1

let the a-1 be x

4x^2-4x-3

4x^2-6x+2x-3

2x(2x-3) +1(2x-3)

(2x-3) (2x+1)

x=a-1

(2(a-1)-3) (2(a-1)+1)

(2a-2-3) (2a-2+1)

Answer 2

$\begin{gathered}\large {\boxed{\sf{\mid{\overline {\underline {\star ANSWER ::}}}\mid}}}\end{gathered}$

To Find :-

$➪ {4(a − 1)}^{2} –4(a – 1) – 3$

Solution :-

$➪ \: 4(a \: − \: 1) {}^{2} \: – \: 4(a \: – \: 1) \: – \: 3 \\ \\ = 4( {a}^{2} - 2(a)(1) + {1}^{2} ) - 4a + 4 - 3 \\ \\ = 4 {a}^{2} - 2a + 4 - 4a + 4 - 3 \\ \\ \large \boxed{ = 4 {a}^{2} - 6a + 5}$

@SweetestBitter