Question

4. A 100 ml solution of KOH contains 10 Millie equivalents of KOH that calculate its strength in normality and gram/liter.

Answer 1

Explanation:

since valency factor of KOH is 1 so milli equivalents=millimoles

so moles=10×10^(-3)=10^(-2)

N=equivalent/volume in liter=10^(-2)/10^(-1)

=10^(-1) =0.1N

weight =mole × molecular weight =10^(-2)×56

S=weight/volume in liter=56×10^(-2)/10^(-1) =5.6 g/liter

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