Math, asked by ramani1005, 5 months ago

(4 + a) + 15 = 8(4 + a)
(ii) (2a - 1)^2 +35 = 12(2a- 1)
(iii) (3a +5)^2 +16 = 30a + 50
(iv) a^4 - 29a^2+ 100 = 0
(v) a^6 - 35a^3 +216 = 0
(vi) 6/(a^2)- 5/a +1 =0 (Hint: Let = x)​

Answers

Answered by chnvss719
1

Answer:

(i)=-13/7

(ii)a=(3,4)

(iii)a=+_1

(iv)a=

(v)a=

(vi)a=(3,2)

Step-by-step explanation:

(i)4+a+15=32+8a

19+a-8a-32=0

-7a-13=0

a=13/-7

(ii)4a^2+1-4a+35=24a-12

4a^2-24a-4a+35+12+1=0

4a^2-28a+48=0

a^2-7a+12=0a=3,4

(iii)9a^2+25+16=30a+50

9a^2+25+16-50=0

9a^2-9=0

a=1,-1

(vi)(6-5a+a^2)/a^2=0

6-5a+a^2=0

a=3,2

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