Math, asked by choteandbade5850, 11 hours ago

4^a√2^a = 64 solve the following simultaneously

Answers

Answered by 4734stkabirnav
0

Answer:

4^a / 2^a can be written as (2^2)^a / 2^a.

Which leads to 2^2a / 2^a.

= 2^a (As base is same, powers should be subtracted in case of their division)

Now, 2^a = 64

Which can be rewritten as 2^a = 2^6

Therefore, a=6.

Hope this clarifies.

Similar questions