Question

4. A 20-kg ball is thrown upward with a
speed of 4 m s-1
(a) Find its potential energy when it
reaches the highest point.
(b) Calculate the maximum height it
reaches.​

Answer 1

Answer:

U= 160J

H= 0.8m

Explanation:

u=4 m s-1

v= 0 m s-1

g = 10 m s-2 ~ a

s ~ h

16= 2 ×10×h

h= 0.8 m

potential energy ,U = mgh

U = 20× 10×0.8

U= 160J