-4(a-2b)+8(a-2b)square
factorise it
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take (a-2b) common and in other bracket take ( -4+8) total and = (a-2b) (-4+8)
Answered by
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-4(a-2b)+8(a-2b)²,
taking (a-2b) common here, then we have
(a-2b) [-4+8(a-2b)],
(a-2b) (-4+8a-16b)
taking (a-2b) common here, then we have
(a-2b) [-4+8(a-2b)],
(a-2b) (-4+8a-16b)
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