Math, asked by anchalasrivastwa86, 9 months ago

4(a + b) - 6(a + b)^2​

Answers

Answered by saktibasumatary81
1

Answer:

4(a+b)-6(a+b)^2

=> 2*(a+b)*( 2 - 3 (a+b)) [ Taking out 2*(a+b) ]

=> 2*(a+b)*(2–3a-3b)

Thanks for A2A.

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How do I factorize 4(a+b)-6(a+b)^2?

Well, 4(a+b)-6(a+b)^2

= 4(a+b)-6(a+b)(a+b)

= (a+b)[4–6(a+b)]

= 2(a+b)(2–3a-3b)

Let, (a + b) = x.

Therefore, 4(a+b)-6(a+b) ^2 = 4x - 6x^2 = 2x*(2 - 3x) = 2*(a + b)*(2 - 3a - 3b)

Productivity maximized.

4(a+b)-6(a+b)^2

2×2(a+b)-2×3(a+b)(a+b)

2(a+b)[2–3(a+b)]

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Answered by Niveditha647
0

Answer:

4(a + b) - 6(a + b)^2​

let a + b = x

4x - 6x^2

      or

4a + 4b - 6 ( a^2 + 2ab + b^2 )

4a + 4b - 6 a^2 - 12ab - 6b^2

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