4(a + b) - 6(a + b)^2
Answers
Answer:
4(a+b)-6(a+b)^2
=> 2*(a+b)*( 2 - 3 (a+b)) [ Taking out 2*(a+b) ]
=> 2*(a+b)*(2–3a-3b)
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How do I factorize 4(a+b)-6(a+b)^2?
Well, 4(a+b)-6(a+b)^2
= 4(a+b)-6(a+b)(a+b)
= (a+b)[4–6(a+b)]
= 2(a+b)(2–3a-3b)
Let, (a + b) = x.
Therefore, 4(a+b)-6(a+b) ^2 = 4x - 6x^2 = 2x*(2 - 3x) = 2*(a + b)*(2 - 3a - 3b)
Productivity maximized.
4(a+b)-6(a+b)^2
2×2(a+b)-2×3(a+b)(a+b)
2(a+b)[2–3(a+b)]
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Answer:
4(a + b) - 6(a + b)^2
let a + b = x
4x - 6x^2
or
4a + 4b - 6 ( a^2 + 2ab + b^2 )
4a + 4b - 6 a^2 - 12ab - 6b^2
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