Question

4(a + b) – 6(a + b)whole2
how to do this sum ​

Answer 1

Answer:

4(a+b) − 6(a + b)²

4(a+b) − 6(a + b)²= (a + b)(4-6(a+b))

4(a+b) − 6(a + b)²= (a + b)(4-6(a+b))= (a + b)(4 - 6a - 6b)

here is your answer

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or

(a+b)(4-6(a+b))

take 2 common

(a+b)(2)(2-3(a+b))

2(a+b)(2-3(a+b))

answer is correct but more simplified

Answer 2

Answer:

How do I factorize 4(a+b)-6(a+b)^2?

Well, 4(a+b)-6(a+b)^2

= 4(a+b)-6(a+b)(a+b)

= (a+b)[4–6(a+b)]

= 2(a+b)(2–3a-3b)