Question

4. A bag contains 3 red and 7 green balls. One ball is drawn at random from the bag. Find the probability of getting (i) a red ball (ii) a green ball.​

Answer 1

Step-by-step explanation:

Total no. of red ball = 3

Total no. of green ball = 7

Total no. of balls = 3 + 7 = 10

(1) probability of getting red ball = 3/ 10

(2) probability of getting green ball = 7/10

Answer 2

Answer:

(ii) a green ball. ✔

Step-by-step explanation:

Given information

• ↬ A bag contains 3 red and 7 green balls.
• ↬ One ball is drawn at random from the bag .

What we need to calculate

• ↬ The probability of getting which ball ?

Formula need

• $\textbf {\: ⇶ \:The formula for probability = }\red{ \bf\dfrac{Favable \: \: outcome}{Total \: \: outcome}}$

Solution

❍ In question it is mentioned that the there are 3 red balls and 7 green balls in the bag .

So, the total outcome for the event of drawing at random from the bag is .

⇥ Total outcome = 3 + 7

⇥ Total outcome = 10

Now , for favorable outcome for getting a red ball , we need to count the total number of red balls which is given as 3 in the question

Therefore ,

• ⇥ Favorable outcomes = 3

❑ Now, using the formula for calculating the probability of getting a red ball

$\\ \\ \red ➥ \: \bf \: From \: the \: bag = \dfrac{Favorable \: \: outcome }{Total \: \: outcome } \\ \\ \\ \red➥ \: \bf \: From \: the \: bag = \: \frac{3}{10}$

Therefore Probability of getting red ball is 3/10

Similarly, for finding the probability getting green ball

$\\ \\ \green ➥ \: \bf \: From \: the \: bag = \dfrac{Favorable \: \: outcome }{Total \: \: outcome } \\ \\ \\ \green➥ \: \bf \: From \: the \: bag = \: \frac{7}{10}$

☆Hence probability of getting green ball from the bag is more then red ball