Question

4.
A ball of mass 200g is on one end of a string of length 20cm. It is revolved in a horizontal circle 29
angular frequency of 6 rpm the angular velocity is.
lal
2n
7a
31
a) rads-
b)
rad s)
c)
d)
-rads-
10.
5
3
5
5
NT
-1
rads-
solution please​

Answer 1

Correct Question :

A ball of mass 200 g is tied to one end of a string of length 20 cm. It is revolved in a horizantal circle at an angular frequency of 6 rpm. Then, angular velocity is

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AnswEr :

Here, they've provided us with the information that, there's a ball of mass 200 g which is tied to one end of a string. Further, the length of string is 20 cm.

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So, we've to find the Angular velocity.

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• Mass of the ball = 200 g

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• Radius of the ball = 20 cm = 0.2 m

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• Angular frequency(n) = 6 rpm = 6/60 = 0.10 rotations/sec.

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Also, we know that,

Angular velocity is the rate of change of the position of a body with respect to the time.

So,

Required formula :

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Angular velocity (ω) = 2 π f

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where,

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• ω = Angular velocity

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• f = Angular frequency

Now, proceeding towards the question,

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Substituting the values :

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$:\implies$ ω = 2 π f

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$:\implies$ ω = 2 π × 0.10

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$:\implies$ ω = 0.2 π

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$:\implies$ ω = 0.2 × 3.14

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$:\implies$ ω = 0.628 rad/sec.

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$\therefore$ Angular velocity is 0.628 rad/sec.