4. A block of mass 30 kg is pulled up a slope with a constant speed by
applying a force of 200 N parallel to the slope
from the initial position A to the final position B.
(a) Calculate :
(i) the work done by the force in moving the
block from A to B, and
(ii) the potential energy gained by the block.
Take : g = 10 m s-2
(b) Account for the difference
in answers to parts
(i) and (ii).
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Answers
Answer:
a) Given : m = 30 kg, F = 200 N, AB = 3 m andCB = 1.5 m.(i) Work done by the force in moving the block from Ato B= Force x displacement in the direction of force.or W = F x AB= 200 NX 3 m = 600 J(ii) The potential energy gained by the block U = mghwhere h = CB = 1.5 m: U = 30 x 10 x 1.5 = 450 J(b) Out of the work done 600 J, only 450 J is the usefulwork which raises the potential energy of the blockand the remaining work = 600 J - 450 J = 150 J isspent against the force of friction between theblock and the slope which gets converted into heatenergy.
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Answer:
A to B = 200 N × 3m = 600 J
(ii) Gain in potential energy = mgh = 30 × 10 × 1.5 = 450 J.
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