Question

4.
A block of mass 6 kg is kept on rough surface as shown in figure. Find
acceleration and friction force acting on the block.
(Take g = 10 m/s)​

Answer 1

Hello Friend,

You forgot to post a figure showing angle of inclination.

◆ Answer -

a = 10.cosθ

F = 60.cosθ

● Explanation -

Let θ be the angle of inclination between rough surface & horizontal.

Acceleration acting on the block will be -

a = g.cosθ

a = 10.cosθ

Frictional force acting on the block will be -

F = m.a

F = 6 × 10.cosθ

F = 60.cosθ

You can further calculate the values of frictional force & acceleration with respective angle of inclination.

Thanks for asking..