Question

4.) A body decelerates uniformly From a 32.0 to a stop in 1.50 minutes.What is its acceleration?
​

Answer 1

Here,
Initial velocity(u)= 32 m/s
Time= 1.5 mins=1.5*60 mins=90 mins
Final velocity(v)=0 m/s
Now,
Acceleration(a)=(u-v)/2
=(32-0)/90
=32/90
=0.3556 m/s^2

Hence, the acceleration of the body is 0.3556 m/s^2