Question

4) A body is projected with a velocity of 20m/s at an angle of 600 with the vertical. Find the maximum height, time of flight and the horizontal range.​

Answer 1

Answer:

HEYYYYY THIS IS THE ANSWERRR

Explanation:

Given :  u=20 m/s     θ=30  

o

      g=10 m/s  

2

 

We get  sinθ=sin30  

o

=  

2

1

​

 

Maximum height reached   H=  

2g u  2  sin  2 θ ​=  20

20×20×(  2 1  )  2

 =5m