Question

4
A body of mass 10Kg is suspended by a rope of 50cm long and pulled to a side through a horizontal
distance of 30 cm by means of a horizontal force. Then that horizontal force is
al 75 Kg - we b) 15 Kg -wt c) 20 Kg - w
d) 30 Kg -wt

Answer 1

Answer:

75 N

Explanation:

See the image for solutions

Answer 2

tan theta = 30/40 = 3/4

F=mg tantheta

F= 100×3/4

= 7.5 N

= 75kg.wt