Question

4. A body of mass 5 kg is taken 1 poir
from a height of 3 m to 6 m.
Find the increase in the
potential energy of the body.
Take g= 10 N/kg.​

Answer 1

Answer:

m=5kg,h

1

=5m,h

2

=10m,g=10ms

−2

Increase in potential energy =(final potential energy) − (initial potential energy) = mg×(h

2

−h

1

)=5×10×(10−5)=250J

Explanation:

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Answer 2

Answer:-

$\pink{\bigstar}$ Increase in Potential Energy is $\large\leadsto\boxed{\tt\purple{150 \: J}}$

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• Given:-

Mass of the body = 5 kg

Initial height of body = 3 m

Final height of body = 6 m

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• To Find:-

Increase in the Potential Energy = ?

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• Solution:-

We know,

$\pink{\bigstar}$ $\large\underline{\boxed{\bf\green{P.E = mgh}}}$

where,

P.E = Potential Energy

m = mass of the body

g = acceleration due to gravity

h = height of the body

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here,

m = 5kg

g = 10 m/s²

h1 = 3m

h2 = 6m

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✯ Applying the above Formula:-

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$\pink{\bigstar}$ $\underline{\boxed{\bf\green{P.E_{(final)} - P.E_{(initial)} = mg \times (h_2 - h_1)}}}$

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• Substituting in the Formula:-

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➪ $\sf P.E_{(increase)} = 5 \times 10 \times (6 - 3)$

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➪ $\sf P.E_{(increase)} = 50 \times 3$

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★ $\large{\bf\red{P.E_{(increase)} = 150 \: J}}$

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Therefore, the increase in Potential Energy will be 150 J.