Question

4. A body of mass m is projected vertically with a
velocity vo. If it passes through the point of
projection with speed
the work done by air
resistance is
3mv?
(1) Zero
(2)
(3)
3my!
4
-3mv.
8​

Answer 1

Answer:

PLZ mark brainlist

Explanation:

So horizontal velocity which remains constant is vcos45

0

=

2

2

v

At highest point of the motion its vertical velocity will be zero and it will possess only horizontal velocity

and the perpendicular distance of velocity vector from the starting point will be equal to the height at

that time i.e. maximum height H

So r=H=

2g

v

2

sin

2

45

0

=

4g

v

2

So the angular momentum is p=mvcos45

0

r=

2

2

×4g

mv×v

2