Question

4) A box contains 5 red, 8 blue and 3 green pens. What is the probability that the pen
picked up is blue?
15-0​

Answer 1

Answer:

Let 5 red pens be R1 , R2 , R3 , R4 , R5 . 8 blue pens be B1 , B2 , B3 , B4 , B5 , B6 , B7 , B8 . and 3 green pens be G1 , G2 , G3 . Sample space, S = {R1 , R2 , R3 , R4 , R5, B1 , B2 , B3 , B4 , B5 , B6 , B7 , B8, G1 , G2 , G3 } ∴ n(S) = 16 Let A be the event that Rutuja picks a blue pen. ∴ A = {B1 , B2 , B3 , B4 , B5 , B6 , B7 , B8} ∴ n(A) = 8 ∴ P(A) = n(A)n(S)n(A)n(S)= 8/16 ∴ P(A) = 1/2 ∴ The probability that Rutuja picks a blue pen is 1/2 .Read more on Sarthaks.com - https://www.sarthaks.com/847578/box-contains-blue-and-green-pens-rutuja-wants-pick-pen-random-what-probability-that-the-blue

Answer 2

Answer:

Question

❇️A box contains 5 red, 8 blue and 3 green pens. What is the probability that the pen

picked up is blue?

Solution ⬇️

✍️S={Red + Blue + Green}={5+8+3}={16}

✍️n(S)=16

• Let A be the event of picking up blue ball

✍️A={8}

✍️n(A)=8

$= = > p(a) = \frac{n(a)}{n(s)} = \frac{8}{16} = \frac{1}{2}$

$= = > therefore \: . \: the \: probability \: of \: getting \: blue \: ball \: is \: \frac{1}{2}$

Explanation:

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