Question

4.a. Calculate the oxidation number of
S in H2S and H202
b.2Mg + 02 --------> 2MgO
Identify the substance oxidized and
reduced?
Identify oxidizing and reducing agent
(4)​

Answer 1

Answer:

4.a)The oxidation number of S in H2S is -2and the oxidation no of Ois -1.

Explanation:

b) 2Mg+O2 ======> 2Mgo

here, in the product side Mgo is oxidized , in the reactant side Mg is reduced.

1)oxidizing agent means the elements or compound that gains electron from a compound after reaction ,ex HNO3 .

2) Reducong agent means the elements or compound that loses an electron to an electron recipient in a redox chemical reaction .